(b-4)/6=b-2

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Solution for (b-4)/6=b-2 equation:



(b-4)/6=b-2
We move all terms to the left:
(b-4)/6-(b-2)=0
We get rid of parentheses
(b-4)/6-b+2=0
We multiply all the terms by the denominator
(b-4)-b*6+2*6=0
We add all the numbers together, and all the variables
(b-4)-b*6+12=0
Wy multiply elements
(b-4)-6b+12=0
We get rid of parentheses
b-6b-4+12=0
We add all the numbers together, and all the variables
-5b+8=0
We move all terms containing b to the left, all other terms to the right
-5b=-8
b=-8/-5
b=1+3/5

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