(b-4c)-(-3b-c)=

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Solution for (b-4c)-(-3b-c)= equation:


Simplifying
(b + -4c) + -1(-3b + -1c) = 0

Remove parenthesis around (b + -4c)
b + -4c + -1(-3b + -1c) = 0
b + -4c + (-3b * -1 + -1c * -1) = 0
b + -4c + (3b + 1c) = 0

Reorder the terms:
b + 3b + -4c + 1c = 0

Combine like terms: b + 3b = 4b
4b + -4c + 1c = 0

Combine like terms: -4c + 1c = -3c
4b + -3c = 0

Solving
4b + -3c = 0

Solving for variable 'b'.

Move all terms containing b to the left, all other terms to the right.

Add '3c' to each side of the equation.
4b + -3c + 3c = 0 + 3c

Combine like terms: -3c + 3c = 0
4b + 0 = 0 + 3c
4b = 0 + 3c
Remove the zero:
4b = 3c

Divide each side by '4'.
b = 0.75c

Simplifying
b = 0.75c

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