(b-5)(b-5)=

Solution for (b-5)(b-5)= equation:

Simplifying
(b + -5)(b + -5) = 0

Reorder the terms:
(-5 + b)(b + -5) = 0

Reorder the terms:
(-5 + b)(-5 + b) = 0

Multiply (-5 + b) * (-5 + b)
(-5(-5 + b) + b(-5 + b)) = 0
((-5 * -5 + b * -5) + b(-5 + b)) = 0
((25 + -5b) + b(-5 + b)) = 0
(25 + -5b + (-5 * b + b * b)) = 0
(25 + -5b + (-5b + b2)) = 0

Combine like terms: -5b + -5b = -10b
(25 + -10b + b2) = 0

Solving
25 + -10b + b2 = 0

Solving for variable 'b'.

Factor a trinomial.
(5 + -1b)(5 + -1b) = 0

Subproblem 1
Set the factor '(5 + -1b)' equal to zero and attempt to solve:

Simplifying
5 + -1b = 0

Solving
5 + -1b = 0

Move all terms containing b to the left, all other terms to the right.

Add '-5' to each side of the equation.
5 + -5 + -1b = 0 + -5

Combine like terms: 5 + -5 = 0
0 + -1b = 0 + -5
-1b = 0 + -5

Combine like terms: 0 + -5 = -5
-1b = -5

Divide each side by '-1'.
b = 5

Simplifying
b = 5
Subproblem 2
Set the factor '(5 + -1b)' equal to zero and attempt to solve:

Simplifying
5 + -1b = 0

Solving
5 + -1b = 0

Move all terms containing b to the left, all other terms to the right.

Add '-5' to each side of the equation.
5 + -5 + -1b = 0 + -5

Combine like terms: 5 + -5 = 0
0 + -1b = 0 + -5
-1b = 0 + -5

Combine like terms: 0 + -5 = -5
-1b = -5

Divide each side by '-1'.
b = 5

Simplifying
b = 5
Solution
b = {5, 5}