(b-5)(b=5)

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Solution for (b-5)(b=5) equation: 



(b-5)(b=5)

We move all terms to the left:

(b-5)(b-(5))=0

We multiply parentheses ..

(+b^2-5b-5b+25)=0

We get rid of parentheses

b^2-5b-5b+25=0

We add all the numbers together, and all the variables

b^2-10b+25=0

a = 1; b = -10; c = +25;
Δ = b2-4ac
Δ = -102-4·1·25
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$b=\frac{-b}{2a}=\frac{10}{2}=5$

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