(b-6)3=12

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Solution for (b-6)3=12 equation: 



(b-6)3=12

We move all terms to the left:

(b-6)3-(12)=0

We multiply parentheses

3b-18-12=0

We add all the numbers together, and all the variables

3b-30=0

We move all terms containing b to the left, all other terms to the right

3b=30

b=30/3

b=10

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