(b-7)(2b+16)=0

Solution for (b-7)(2b+16)=0 equation:

(b-7)(2b+16)=0

We multiply parentheses ..

(+2b^2+16b-14b-112)=0

We get rid of parentheses

2b^2+16b-14b-112=0

We add all the numbers together, and all the variables

2b^2+2b-112=0

a = 2; b = 2; c = -112;
Δ = b2-4ac
Δ = 22-4·2·(-112)
Δ = 900
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{900}=30$
$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(2)-30}{2*2}=\frac{-32}{4}
=-8
$
$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(2)+30}{2*2}=\frac{28}{4}
=7
$