(b-7)(b+5)=b+8)(b-9)

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Solution for (b-7)(b+5)=b+8)(b-9) equation: 



(b-7)(b+5)=b+8)(b-9)

We move all terms to the left:

(b-7)(b+5)-(b+8)(b-9))=0

We multiply parentheses ..

(+b^2+5b-7b-35)-(b+8)(b-9))=0

We get rid of parentheses

b^2+5b-7b-(b+8)(b-9))-35=0

We multiply parentheses ..

b^2-(+b^2-9b+8b-72))-35+5b-7b=0

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