(b-7)/4=(b+2)/3

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Solution for (b-7)/4=(b+2)/3 equation:



(b-7)/4=(b+2)/3
We move all terms to the left:
(b-7)/4-((b+2)/3)=0
We calculate fractions
b/()+(-((b+2)*4)/()=0
We calculate terms in parentheses: +(-((b+2)*4)/(), so:
-((b+2)*4)/(
We multiply all the terms by the denominator
-((b+2)*4)
We calculate terms in parentheses: -((b+2)*4), so:
(b+2)*4
We multiply parentheses
4b+8
Back to the equation:
-(4b+8)
We get rid of parentheses
-4b-8
Back to the equation:
+(-4b-8)
We get rid of parentheses
b/()-4b-8=0
We multiply all the terms by the denominator
b-4b*()-8*()=0
We add all the numbers together, and all the variables
b-4b*()=0

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