(b-7)/4=(b+2)/3

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Solution for (b-7)/4=(b+2)/3 equation: 



(b-7)/4=(b+2)/3

We move all terms to the left:

(b-7)/4-((b+2)/3)=0

We calculate fractions


b/()+(-((b+2)*4)/()=0



We calculate terms in parentheses: +(-((b+2)*4)/(), so:

-((b+2)*4)/(

We multiply all the terms by the denominator


-((b+2)*4)



We calculate terms in parentheses: -((b+2)*4), so:

(b+2)*4

We multiply parentheses

4b+8

Back to the equation:

-(4b+8)



We get rid of parentheses

-4b-8

Back to the equation:

+(-4b-8)



We get rid of parentheses

b/()-4b-8=0

We multiply all the terms by the denominator


b-4b*()-8*()=0

We add all the numbers together, and all the variables

b-4b*()=0

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