(b-7)/5=(b+3)/4

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Solution for (b-7)/5=(b+3)/4 equation: 



(b-7)/5=(b+3)/4

We move all terms to the left:

(b-7)/5-((b+3)/4)=0

We calculate fractions


b/()+(-((b+3)*5)/()=0



We calculate terms in parentheses: +(-((b+3)*5)/(), so:

-((b+3)*5)/(

We multiply all the terms by the denominator


-((b+3)*5)



We calculate terms in parentheses: -((b+3)*5), so:

(b+3)*5

We multiply parentheses

5b+15

Back to the equation:

-(5b+15)



We get rid of parentheses

-5b-15

Back to the equation:

+(-5b-15)



We get rid of parentheses

b/()-5b-15=0

We multiply all the terms by the denominator


b-5b*()-15*()=0

We add all the numbers together, and all the variables

b-5b*()=0

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