(b-8)(b+2)=

Solution for (b-8)(b+2)= equation:

Simplifying
(b + -8)(b + 2) = 0

Reorder the terms:
(-8 + b)(b + 2) = 0

Reorder the terms:
(-8 + b)(2 + b) = 0

Multiply (-8 + b) * (2 + b)
(-8(2 + b) + b(2 + b)) = 0
((2 * -8 + b * -8) + b(2 + b)) = 0
((-16 + -8b) + b(2 + b)) = 0
(-16 + -8b + (2 * b + b * b)) = 0
(-16 + -8b + (2b + b2)) = 0

Combine like terms: -8b + 2b = -6b
(-16 + -6b + b2) = 0

Solving
-16 + -6b + b2 = 0

Solving for variable 'b'.

Factor a trinomial.
(-2 + -1b)(8 + -1b) = 0

Subproblem 1
Set the factor '(-2 + -1b)' equal to zero and attempt to solve:

Simplifying
-2 + -1b = 0

Solving
-2 + -1b = 0

Move all terms containing b to the left, all other terms to the right.

Add '2' to each side of the equation.
-2 + 2 + -1b = 0 + 2

Combine like terms: -2 + 2 = 0
0 + -1b = 0 + 2
-1b = 0 + 2

Combine like terms: 0 + 2 = 2
-1b = 2

Divide each side by '-1'.
b = -2

Simplifying
b = -2
Subproblem 2
Set the factor '(8 + -1b)' equal to zero and attempt to solve:

Simplifying
8 + -1b = 0

Solving
8 + -1b = 0

Move all terms containing b to the left, all other terms to the right.

Add '-8' to each side of the equation.
8 + -8 + -1b = 0 + -8

Combine like terms: 8 + -8 = 0
0 + -1b = 0 + -8
-1b = 0 + -8

Combine like terms: 0 + -8 = -8
-1b = -8

Divide each side by '-1'.
b = 8

Simplifying
b = 8
Solution
b = {-2, 8}