(b-8)(b+2)=

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Solution for (b-8)(b+2)= equation:


Simplifying
(b + -8)(b + 2) = 0

Reorder the terms:
(-8 + b)(b + 2) = 0

Reorder the terms:
(-8 + b)(2 + b) = 0

Multiply (-8 + b) * (2 + b)
(-8(2 + b) + b(2 + b)) = 0
((2 * -8 + b * -8) + b(2 + b)) = 0
((-16 + -8b) + b(2 + b)) = 0
(-16 + -8b + (2 * b + b * b)) = 0
(-16 + -8b + (2b + b2)) = 0

Combine like terms: -8b + 2b = -6b
(-16 + -6b + b2) = 0

Solving
-16 + -6b + b2 = 0

Solving for variable 'b'.

Factor a trinomial.
(-2 + -1b)(8 + -1b) = 0

Subproblem 1

Set the factor '(-2 + -1b)' equal to zero and attempt to solve: Simplifying -2 + -1b = 0 Solving -2 + -1b = 0 Move all terms containing b to the left, all other terms to the right. Add '2' to each side of the equation. -2 + 2 + -1b = 0 + 2 Combine like terms: -2 + 2 = 0 0 + -1b = 0 + 2 -1b = 0 + 2 Combine like terms: 0 + 2 = 2 -1b = 2 Divide each side by '-1'. b = -2 Simplifying b = -2

Subproblem 2

Set the factor '(8 + -1b)' equal to zero and attempt to solve: Simplifying 8 + -1b = 0 Solving 8 + -1b = 0 Move all terms containing b to the left, all other terms to the right. Add '-8' to each side of the equation. 8 + -8 + -1b = 0 + -8 Combine like terms: 8 + -8 = 0 0 + -1b = 0 + -8 -1b = 0 + -8 Combine like terms: 0 + -8 = -8 -1b = -8 Divide each side by '-1'. b = 8 Simplifying b = 8

Solution

b = {-2, 8}

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