(b-8)(b-8)=

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Solution for (b-8)(b-8)= equation: 



(b-8)(b-8)=

We move all terms to the left:

(b-8)(b-8)-()=0

We add all the numbers together, and all the variables

(b-8)(b-8)=0

We multiply parentheses ..

(+b^2-8b-8b+64)=0

We get rid of parentheses

b^2-8b-8b+64=0

We add all the numbers together, and all the variables

b^2-16b+64=0

a = 1; b = -16; c = +64;
Δ = b2-4ac
Δ = -162-4·1·64
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$b=\frac{-b}{2a}=\frac{16}{2}=8$

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