(b-8)/3=(b+5)/2

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Solution for (b-8)/3=(b+5)/2 equation: 



(b-8)/3=(b+5)/2

We move all terms to the left:

(b-8)/3-((b+5)/2)=0

We calculate fractions


b/()+(-((b+5)*3)/()=0



We calculate terms in parentheses: +(-((b+5)*3)/(), so:

-((b+5)*3)/(

We multiply all the terms by the denominator


-((b+5)*3)



We calculate terms in parentheses: -((b+5)*3), so:

(b+5)*3

We multiply parentheses

3b+15

Back to the equation:

-(3b+15)



We get rid of parentheses

-3b-15

Back to the equation:

+(-3b-15)



We get rid of parentheses

b/()-3b-15=0

We multiply all the terms by the denominator


b-3b*()-15*()=0

We add all the numbers together, and all the variables

b-3b*()=0

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