(b-9)(b+4)=b2-11

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Solution for (b-9)(b+4)=b2-11 equation:



(b-9)(b+4)=b2-11
We move all terms to the left:
(b-9)(b+4)-(b2-11)=0
We add all the numbers together, and all the variables
-(+b^2-11)+(b-9)(b+4)=0
We get rid of parentheses
-b^2+(b-9)(b+4)+11=0
We multiply parentheses ..
-b^2+(+b^2+4b-9b-36)+11=0
We add all the numbers together, and all the variables
-1b^2+(+b^2+4b-9b-36)+11=0
We get rid of parentheses
-1b^2+b^2+4b-9b-36+11=0
We add all the numbers together, and all the variables
-5b-25=0
We move all terms containing b to the left, all other terms to the right
-5b=25
b=25/-5
b=-5

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