(b-a)(b+a)=

Solution for (b-a)(b+a)= equation:

Simplifying
(b + -1a)(b + a) = 0

Reorder the terms:
(-1a + b)(b + a) = 0

Reorder the terms:
(-1a + b)(a + b) = 0

Multiply (-1a + b) * (a + b)
(-1a * (a + b) + b(a + b)) = 0
((a * -1a + b * -1a) + b(a + b)) = 0

Reorder the terms:
((-1ab + -1a2) + b(a + b)) = 0
((-1ab + -1a2) + b(a + b)) = 0
(-1ab + -1a2 + (a * b + b * b)) = 0
(-1ab + -1a2 + (ab + b2)) = 0

Reorder the terms:
(-1ab + ab + -1a2 + b2) = 0

Combine like terms: -1ab + ab = 0
(0 + -1a2 + b2) = 0
(-1a2 + b2) = 0

Solving
-1a2 + b2 = 0

Solving for variable 'a'.

Move all terms containing a to the left, all other terms to the right.

Add '-1b2' to each side of the equation.
-1a2 + b2 + -1b2 = 0 + -1b2

Combine like terms: b2 + -1b2 = 0
-1a2 + 0 = 0 + -1b2
-1a2 = 0 + -1b2
Remove the zero:
-1a2 = -1b2

Divide each side by '-1'.
a2 = b2

Simplifying
a2 = b2

Take the square root of each side:
a = {-1b, b}