(b-g)(b-g)=0

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Solution for (b-g)(b-g)=0 equation:


Simplifying
(b + -1g)(b + -1g) = 0

Multiply (b + -1g) * (b + -1g)
(b(b + -1g) + -1g * (b + -1g)) = 0
((b * b + -1g * b) + -1g * (b + -1g)) = 0

Reorder the terms:
((-1bg + b2) + -1g * (b + -1g)) = 0
((-1bg + b2) + -1g * (b + -1g)) = 0
(-1bg + b2 + (b * -1g + -1g * -1g)) = 0
(-1bg + b2 + (-1bg + 1g2)) = 0

Reorder the terms:
(-1bg + -1bg + b2 + 1g2) = 0

Combine like terms: -1bg + -1bg = -2bg
(-2bg + b2 + 1g2) = 0

Solving
-2bg + b2 + 1g2 = 0

Solving for variable 'b'.

Factor a trinomial.
(b + -1g)(b + -1g) = 0

Subproblem 1

Set the factor '(b + -1g)' equal to zero and attempt to solve: Simplifying b + -1g = 0 Solving b + -1g = 0 Move all terms containing b to the left, all other terms to the right. Add 'g' to each side of the equation. b + -1g + g = 0 + g Combine like terms: -1g + g = 0 b + 0 = 0 + g b = 0 + g Remove the zero: b = g Simplifying b = g

Subproblem 2

Set the factor '(b + -1g)' equal to zero and attempt to solve: Simplifying b + -1g = 0 Solving b + -1g = 0 Move all terms containing b to the left, all other terms to the right. Add 'g' to each side of the equation. b + -1g + g = 0 + g Combine like terms: -1g + g = 0 b + 0 = 0 + g b = 0 + g Remove the zero: b = g Simplifying b = g

Solution

b = {g, g}

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