(b/2)+(3/b)

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Solution for (b/2)+(3/b) equation: 


D( b )

b = 0

b = 0

b = 0

b in (-oo:0) U (0:+oo)

b/2+3/b = 0

1/2*b^1+3*b^-1 = 0

(1/2*b^2+3*b^0)/(b^1) = 0 // * b^2

b^1*(1/2*b^2+3*b^0) = 0

b^1

(1/2)*b^2+3 = 0

(1/2)*b^2+3 = 0

DELTA = 0^2-(3*4*(1/2))

DELTA = -6

DELTA < 0

b in { } 

b belongs to the empty set

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