(b/2)+(3/b)=8

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Solution for (b/2)+(3/b)=8 equation: 


D( b )

b = 0

b = 0

b = 0

b in (-oo:0) U (0:+oo)

b/2+3/b = 8 // - 8

b/2+3/b-8 = 0

1/2*b^1+3*b^-1-8*b^0 = 0

(1/2*b^2-8*b^1+3*b^0)/(b^1) = 0 // * b^2

b^1*(1/2*b^2-8*b^1+3*b^0) = 0

b^1

(1/2)*b^2-8*b+3 = 0

(1/2)*b^2-8*b+3 = 0

DELTA = (-8)^2-(3*4*(1/2))

DELTA = 58

DELTA > 0

b = (58^(1/2)+8)/(2*(1/2)) or b = (8-58^(1/2))/(2*(1/2))

b = 58^(1/2)+8 or b = 8-58^(1/2)

b in { 8-58^(1/2), 58^(1/2)+8} 

b in { 8-58^(1/2), 58^(1/2)+8 }

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