(b=2)(b-1)=0

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Solution for (b=2)(b-1)=0 equation: 



(b=2)(b-1)=0

We move all terms to the left:

(b-(2)(b-1))=0



We calculate terms in parentheses: +(b-2(b-1)), so:

b-2(b-1)

We multiply parentheses

b-2b+2

We add all the numbers together, and all the variables

-1b+2

Back to the equation:

+(-1b+2)



We get rid of parentheses

-1b+2=0

We move all terms containing b to the left, all other terms to the right

-b=-2

b=-2/-1

b=+2

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