(c+)-2c-(1-3c)=2

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Solution for (c+)-2c-(1-3c)=2 equation: 



(c+)-2c-(1-3c)=2

We move all terms to the left:

(c+)-2c-(1-3c)-(2)=0

We add all the numbers together, and all the variables

(+c)-2c-(-3c+1)-2=0

We add all the numbers together, and all the variables

-2c+(+c)-(-3c+1)-2=0

We get rid of parentheses

-2c+c+3c-1-2=0

We add all the numbers together, and all the variables

2c-3=0

We move all terms containing c to the left, all other terms to the right

2c=3

c=3/2

c=1+1/2

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