(c+1)+48+3c=

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Solution for (c+1)+48+3c= equation:


Simplifying
(c + 1) + 48 + 3c = 0

Reorder the terms:
(1 + c) + 48 + 3c = 0

Remove parenthesis around (1 + c)
1 + c + 48 + 3c = 0

Reorder the terms:
1 + 48 + c + 3c = 0

Combine like terms: 1 + 48 = 49
49 + c + 3c = 0

Combine like terms: c + 3c = 4c
49 + 4c = 0

Solving
49 + 4c = 0

Solving for variable 'c'.

Move all terms containing c to the left, all other terms to the right.

Add '-49' to each side of the equation.
49 + -49 + 4c = 0 + -49

Combine like terms: 49 + -49 = 0
0 + 4c = 0 + -49
4c = 0 + -49

Combine like terms: 0 + -49 = -49
4c = -49

Divide each side by '4'.
c = -12.25

Simplifying
c = -12.25

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