(c+1)2=4(c-2)

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Solution for (c+1)2=4(c-2) equation:


Simplifying
(c + 1) * 2 = 4(c + -2)

Reorder the terms:
(1 + c) * 2 = 4(c + -2)

Reorder the terms for easier multiplication:
2(1 + c) = 4(c + -2)
(1 * 2 + c * 2) = 4(c + -2)
(2 + 2c) = 4(c + -2)

Reorder the terms:
2 + 2c = 4(-2 + c)
2 + 2c = (-2 * 4 + c * 4)
2 + 2c = (-8 + 4c)

Solving
2 + 2c = -8 + 4c

Solving for variable 'c'.

Move all terms containing c to the left, all other terms to the right.

Add '-4c' to each side of the equation.
2 + 2c + -4c = -8 + 4c + -4c

Combine like terms: 2c + -4c = -2c
2 + -2c = -8 + 4c + -4c

Combine like terms: 4c + -4c = 0
2 + -2c = -8 + 0
2 + -2c = -8

Add '-2' to each side of the equation.
2 + -2 + -2c = -8 + -2

Combine like terms: 2 + -2 = 0
0 + -2c = -8 + -2
-2c = -8 + -2

Combine like terms: -8 + -2 = -10
-2c = -10

Divide each side by '-2'.
c = 5

Simplifying
c = 5

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