(c+12)+(4c+19)+(c+17)=180

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Solution for (c+12)+(4c+19)+(c+17)=180 equation: 



(c+12)+(4c+19)+(c+17)=180

We move all terms to the left:

(c+12)+(4c+19)+(c+17)-(180)=0

We get rid of parentheses

c+4c+c+12+19+17-180=0

We add all the numbers together, and all the variables

6c-132=0

We move all terms containing c to the left, all other terms to the right

6c=132

c=132/6

c=22

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