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Simplifying (c + 2)(c + -9) = 0 Reorder the terms: (2 + c)(c + -9) = 0 Reorder the terms: (2 + c)(-9 + c) = 0 Multiply (2 + c) * (-9 + c) (2(-9 + c) + c(-9 + c)) = 0 ((-9 * 2 + c * 2) + c(-9 + c)) = 0 ((-18 + 2c) + c(-9 + c)) = 0 (-18 + 2c + (-9 * c + c * c)) = 0 (-18 + 2c + (-9c + c2)) = 0 Combine like terms: 2c + -9c = -7c (-18 + -7c + c2) = 0 Solving -18 + -7c + c2 = 0 Solving for variable 'c'. Factor a trinomial. (-2 + -1c)(9 + -1c) = 0Subproblem 1
Set the factor '(-2 + -1c)' equal to zero and attempt to solve: Simplifying -2 + -1c = 0 Solving -2 + -1c = 0 Move all terms containing c to the left, all other terms to the right. Add '2' to each side of the equation. -2 + 2 + -1c = 0 + 2 Combine like terms: -2 + 2 = 0 0 + -1c = 0 + 2 -1c = 0 + 2 Combine like terms: 0 + 2 = 2 -1c = 2 Divide each side by '-1'. c = -2 Simplifying c = -2Subproblem 2
Set the factor '(9 + -1c)' equal to zero and attempt to solve: Simplifying 9 + -1c = 0 Solving 9 + -1c = 0 Move all terms containing c to the left, all other terms to the right. Add '-9' to each side of the equation. 9 + -9 + -1c = 0 + -9 Combine like terms: 9 + -9 = 0 0 + -1c = 0 + -9 -1c = 0 + -9 Combine like terms: 0 + -9 = -9 -1c = -9 Divide each side by '-1'. c = 9 Simplifying c = 9Solution
c = {-2, 9}
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