(c+2)(c-9)=0

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Solution for (c+2)(c-9)=0 equation:


Simplifying
(c + 2)(c + -9) = 0

Reorder the terms:
(2 + c)(c + -9) = 0

Reorder the terms:
(2 + c)(-9 + c) = 0

Multiply (2 + c) * (-9 + c)
(2(-9 + c) + c(-9 + c)) = 0
((-9 * 2 + c * 2) + c(-9 + c)) = 0
((-18 + 2c) + c(-9 + c)) = 0
(-18 + 2c + (-9 * c + c * c)) = 0
(-18 + 2c + (-9c + c2)) = 0

Combine like terms: 2c + -9c = -7c
(-18 + -7c + c2) = 0

Solving
-18 + -7c + c2 = 0

Solving for variable 'c'.

Factor a trinomial.
(-2 + -1c)(9 + -1c) = 0

Subproblem 1

Set the factor '(-2 + -1c)' equal to zero and attempt to solve: Simplifying -2 + -1c = 0 Solving -2 + -1c = 0 Move all terms containing c to the left, all other terms to the right. Add '2' to each side of the equation. -2 + 2 + -1c = 0 + 2 Combine like terms: -2 + 2 = 0 0 + -1c = 0 + 2 -1c = 0 + 2 Combine like terms: 0 + 2 = 2 -1c = 2 Divide each side by '-1'. c = -2 Simplifying c = -2

Subproblem 2

Set the factor '(9 + -1c)' equal to zero and attempt to solve: Simplifying 9 + -1c = 0 Solving 9 + -1c = 0 Move all terms containing c to the left, all other terms to the right. Add '-9' to each side of the equation. 9 + -9 + -1c = 0 + -9 Combine like terms: 9 + -9 = 0 0 + -1c = 0 + -9 -1c = 0 + -9 Combine like terms: 0 + -9 = -9 -1c = -9 Divide each side by '-1'. c = 9 Simplifying c = 9

Solution

c = {-2, 9}

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