(c+2)-2c-1(1-3c)=2

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Solution for (c+2)-2c-1(1-3c)=2 equation: 



(c+2)-2c-1(1-3c)=2

We move all terms to the left:

(c+2)-2c-1(1-3c)-(2)=0

We add all the numbers together, and all the variables

(c+2)-2c-1(-3c+1)-2=0

We add all the numbers together, and all the variables

-2c+(c+2)-1(-3c+1)-2=0

We get rid of parentheses

-2c+c-1(-3c+1)+2-2=0

We add all the numbers together, and all the variables

-1c-1(-3c+1)=0

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