(c+2)=5(c+1)-7

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Solution for (c+2)=5(c+1)-7 equation:


Simplifying
(c + 2) = 5(c + 1) + -7

Reorder the terms:
(2 + c) = 5(c + 1) + -7

Remove parenthesis around (2 + c)
2 + c = 5(c + 1) + -7

Reorder the terms:
2 + c = 5(1 + c) + -7
2 + c = (1 * 5 + c * 5) + -7
2 + c = (5 + 5c) + -7

Reorder the terms:
2 + c = 5 + -7 + 5c

Combine like terms: 5 + -7 = -2
2 + c = -2 + 5c

Solving
2 + c = -2 + 5c

Solving for variable 'c'.

Move all terms containing c to the left, all other terms to the right.

Add '-5c' to each side of the equation.
2 + c + -5c = -2 + 5c + -5c

Combine like terms: c + -5c = -4c
2 + -4c = -2 + 5c + -5c

Combine like terms: 5c + -5c = 0
2 + -4c = -2 + 0
2 + -4c = -2

Add '-2' to each side of the equation.
2 + -2 + -4c = -2 + -2

Combine like terms: 2 + -2 = 0
0 + -4c = -2 + -2
-4c = -2 + -2

Combine like terms: -2 + -2 = -4
-4c = -4

Divide each side by '-4'.
c = 1

Simplifying
c = 1

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