(c+3)(c+4)=2

Solution for (c+3)(c+4)=2 equation:

Simplifying
(c + 3)(c + 4) = 2

Reorder the terms:
(3 + c)(c + 4) = 2

Reorder the terms:
(3 + c)(4 + c) = 2

Multiply (3 + c) * (4 + c)
(3(4 + c) + c(4 + c)) = 2
((4 * 3 + c * 3) + c(4 + c)) = 2
((12 + 3c) + c(4 + c)) = 2
(12 + 3c + (4 * c + c * c)) = 2
(12 + 3c + (4c + c2)) = 2

Combine like terms: 3c + 4c = 7c
(12 + 7c + c2) = 2

Solving
12 + 7c + c2 = 2

Solving for variable 'c'.

Reorder the terms:
12 + -2 + 7c + c2 = 2 + -2

Combine like terms: 12 + -2 = 10
10 + 7c + c2 = 2 + -2

Combine like terms: 2 + -2 = 0
10 + 7c + c2 = 0

Factor a trinomial.
(5 + c)(2 + c) = 0

Subproblem 1
Set the factor '(5 + c)' equal to zero and attempt to solve:

Simplifying
5 + c = 0

Solving
5 + c = 0

Move all terms containing c to the left, all other terms to the right.

Add '-5' to each side of the equation.
5 + -5 + c = 0 + -5

Combine like terms: 5 + -5 = 0
0 + c = 0 + -5
c = 0 + -5

Combine like terms: 0 + -5 = -5
c = -5

Simplifying
c = -5
Subproblem 2
Set the factor '(2 + c)' equal to zero and attempt to solve:

Simplifying
2 + c = 0

Solving
2 + c = 0

Move all terms containing c to the left, all other terms to the right.

Add '-2' to each side of the equation.
2 + -2 + c = 0 + -2

Combine like terms: 2 + -2 = 0
0 + c = 0 + -2
c = 0 + -2

Combine like terms: 0 + -2 = -2
c = -2

Simplifying
c = -2
Solution
c = {-5, -2}