(c+3)(c-3)=27

Solution for (c+3)(c-3)=27 equation:

Simplifying
(c + 3)(c + -3) = 27

Reorder the terms:
(3 + c)(c + -3) = 27

Reorder the terms:
(3 + c)(-3 + c) = 27

Multiply (3 + c) * (-3 + c)
(3(-3 + c) + c(-3 + c)) = 27
((-3 * 3 + c * 3) + c(-3 + c)) = 27
((-9 + 3c) + c(-3 + c)) = 27
(-9 + 3c + (-3 * c + c * c)) = 27
(-9 + 3c + (-3c + c2)) = 27

Combine like terms: 3c + -3c = 0
(-9 + 0 + c2) = 27
(-9 + c2) = 27

Solving
-9 + c2 = 27

Solving for variable 'c'.

Move all terms containing c to the left, all other terms to the right.

Add '9' to each side of the equation.
-9 + 9 + c2 = 27 + 9

Combine like terms: -9 + 9 = 0
0 + c2 = 27 + 9
c2 = 27 + 9

Combine like terms: 27 + 9 = 36
c2 = 36

Simplifying
c2 = 36

Take the square root of each side:
c = {-6, 6}