(c+3)+2c=21

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Solution for (c+3)+2c=21 equation:


Simplifying
(c + 3) + 2c = 21

Reorder the terms:
(3 + c) + 2c = 21

Remove parenthesis around (3 + c)
3 + c + 2c = 21

Combine like terms: c + 2c = 3c
3 + 3c = 21

Solving
3 + 3c = 21

Solving for variable 'c'.

Move all terms containing c to the left, all other terms to the right.

Add '-3' to each side of the equation.
3 + -3 + 3c = 21 + -3

Combine like terms: 3 + -3 = 0
0 + 3c = 21 + -3
3c = 21 + -3

Combine like terms: 21 + -3 = 18
3c = 18

Divide each side by '3'.
c = 6

Simplifying
c = 6

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