(c+3)-2c-(1+3c)=20

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Solution for (c+3)-2c-(1+3c)=20 equation: 



(c+3)-2c-(1+3c)=20

We move all terms to the left:

(c+3)-2c-(1+3c)-(20)=0

We add all the numbers together, and all the variables

(c+3)-2c-(3c+1)-20=0

We add all the numbers together, and all the variables

-2c+(c+3)-(3c+1)-20=0

We get rid of parentheses

-2c+c-3c+3-1-20=0

We add all the numbers together, and all the variables

-4c-18=0

We move all terms containing c to the left, all other terms to the right

-4c=18

c=18/-4

c=-4+1/2

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