(c+3)-2c-(1-3c)=12

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Solution for (c+3)-2c-(1-3c)=12 equation: 



(c+3)-2c-(1-3c)=12

We move all terms to the left:

(c+3)-2c-(1-3c)-(12)=0

We add all the numbers together, and all the variables

(c+3)-2c-(-3c+1)-12=0

We add all the numbers together, and all the variables

-2c+(c+3)-(-3c+1)-12=0

We get rid of parentheses

-2c+c+3c+3-1-12=0

We add all the numbers together, and all the variables

2c-10=0

We move all terms containing c to the left, all other terms to the right

2c=10

c=10/2

c=5

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