(c+4)(2c+7)=

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Solution for (c+4)(2c+7)= equation:


Simplifying
(c + 4)(2c + 7) = 0

Reorder the terms:
(4 + c)(2c + 7) = 0

Reorder the terms:
(4 + c)(7 + 2c) = 0

Multiply (4 + c) * (7 + 2c)
(4(7 + 2c) + c(7 + 2c)) = 0
((7 * 4 + 2c * 4) + c(7 + 2c)) = 0
((28 + 8c) + c(7 + 2c)) = 0
(28 + 8c + (7 * c + 2c * c)) = 0
(28 + 8c + (7c + 2c2)) = 0

Combine like terms: 8c + 7c = 15c
(28 + 15c + 2c2) = 0

Solving
28 + 15c + 2c2 = 0

Solving for variable 'c'.

Factor a trinomial.
(4 + c)(7 + 2c) = 0

Subproblem 1

Set the factor '(4 + c)' equal to zero and attempt to solve: Simplifying 4 + c = 0 Solving 4 + c = 0 Move all terms containing c to the left, all other terms to the right. Add '-4' to each side of the equation. 4 + -4 + c = 0 + -4 Combine like terms: 4 + -4 = 0 0 + c = 0 + -4 c = 0 + -4 Combine like terms: 0 + -4 = -4 c = -4 Simplifying c = -4

Subproblem 2

Set the factor '(7 + 2c)' equal to zero and attempt to solve: Simplifying 7 + 2c = 0 Solving 7 + 2c = 0 Move all terms containing c to the left, all other terms to the right. Add '-7' to each side of the equation. 7 + -7 + 2c = 0 + -7 Combine like terms: 7 + -7 = 0 0 + 2c = 0 + -7 2c = 0 + -7 Combine like terms: 0 + -7 = -7 2c = -7 Divide each side by '2'. c = -3.5 Simplifying c = -3.5

Solution

c = {-4, -3.5}

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