(c+4)(c+1)=-2

Solution for (c+4)(c+1)=-2 equation:

Simplifying
(c + 4)(c + 1) = -2

Reorder the terms:
(4 + c)(c + 1) = -2

Reorder the terms:
(4 + c)(1 + c) = -2

Multiply (4 + c) * (1 + c)
(4(1 + c) + c(1 + c)) = -2
((1 * 4 + c * 4) + c(1 + c)) = -2
((4 + 4c) + c(1 + c)) = -2
(4 + 4c + (1 * c + c * c)) = -2
(4 + 4c + (1c + c2)) = -2

Combine like terms: 4c + 1c = 5c
(4 + 5c + c2) = -2

Solving
4 + 5c + c2 = -2

Solving for variable 'c'.

Reorder the terms:
4 + 2 + 5c + c2 = -2 + 2

Combine like terms: 4 + 2 = 6
6 + 5c + c2 = -2 + 2

Combine like terms: -2 + 2 = 0
6 + 5c + c2 = 0

Factor a trinomial.
(3 + c)(2 + c) = 0

Subproblem 1
Set the factor '(3 + c)' equal to zero and attempt to solve:

Simplifying
3 + c = 0

Solving
3 + c = 0

Move all terms containing c to the left, all other terms to the right.

Add '-3' to each side of the equation.
3 + -3 + c = 0 + -3

Combine like terms: 3 + -3 = 0
0 + c = 0 + -3
c = 0 + -3

Combine like terms: 0 + -3 = -3
c = -3

Simplifying
c = -3
Subproblem 2
Set the factor '(2 + c)' equal to zero and attempt to solve:

Simplifying
2 + c = 0

Solving
2 + c = 0

Move all terms containing c to the left, all other terms to the right.

Add '-2' to each side of the equation.
2 + -2 + c = 0 + -2

Combine like terms: 2 + -2 = 0
0 + c = 0 + -2
c = 0 + -2

Combine like terms: 0 + -2 = -2
c = -2

Simplifying
c = -2
Solution
c = {-3, -2}