(c+4)3-6c=2(4-2c)

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Solution for (c+4)3-6c=2(4-2c) equation:


Simplifying
(c + 4) * 3 + -6c = 2(4 + -2c)

Reorder the terms:
(4 + c) * 3 + -6c = 2(4 + -2c)

Reorder the terms for easier multiplication:
3(4 + c) + -6c = 2(4 + -2c)
(4 * 3 + c * 3) + -6c = 2(4 + -2c)
(12 + 3c) + -6c = 2(4 + -2c)

Combine like terms: 3c + -6c = -3c
12 + -3c = 2(4 + -2c)
12 + -3c = (4 * 2 + -2c * 2)
12 + -3c = (8 + -4c)

Solving
12 + -3c = 8 + -4c

Solving for variable 'c'.

Move all terms containing c to the left, all other terms to the right.

Add '4c' to each side of the equation.
12 + -3c + 4c = 8 + -4c + 4c

Combine like terms: -3c + 4c = 1c
12 + 1c = 8 + -4c + 4c

Combine like terms: -4c + 4c = 0
12 + 1c = 8 + 0
12 + 1c = 8

Add '-12' to each side of the equation.
12 + -12 + 1c = 8 + -12

Combine like terms: 12 + -12 = 0
0 + 1c = 8 + -12
1c = 8 + -12

Combine like terms: 8 + -12 = -4
1c = -4

Divide each side by '1'.
c = -4

Simplifying
c = -4

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