(c+5)(c+1)=0

Solution for (c+5)(c+1)=0 equation:

Simplifying
(c + 5)(c + 1) = 0

Reorder the terms:
(5 + c)(c + 1) = 0

Reorder the terms:
(5 + c)(1 + c) = 0

Multiply (5 + c) * (1 + c)
(5(1 + c) + c(1 + c)) = 0
((1 * 5 + c * 5) + c(1 + c)) = 0
((5 + 5c) + c(1 + c)) = 0
(5 + 5c + (1 * c + c * c)) = 0
(5 + 5c + (1c + c2)) = 0

Combine like terms: 5c + 1c = 6c
(5 + 6c + c2) = 0

Solving
5 + 6c + c2 = 0

Solving for variable 'c'.

Factor a trinomial.
(5 + c)(1 + c) = 0

Subproblem 1
Set the factor '(5 + c)' equal to zero and attempt to solve:

Simplifying
5 + c = 0

Solving
5 + c = 0

Move all terms containing c to the left, all other terms to the right.

Add '-5' to each side of the equation.
5 + -5 + c = 0 + -5

Combine like terms: 5 + -5 = 0
0 + c = 0 + -5
c = 0 + -5

Combine like terms: 0 + -5 = -5
c = -5

Simplifying
c = -5
Subproblem 2
Set the factor '(1 + c)' equal to zero and attempt to solve:

Simplifying
1 + c = 0

Solving
1 + c = 0

Move all terms containing c to the left, all other terms to the right.

Add '-1' to each side of the equation.
1 + -1 + c = 0 + -1

Combine like terms: 1 + -1 = 0
0 + c = 0 + -1
c = 0 + -1

Combine like terms: 0 + -1 = -1
c = -1

Simplifying
c = -1
Solution
c = {-5, -1}