(c+5)(c+1)=0

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Solution for (c+5)(c+1)=0 equation:


Simplifying
(c + 5)(c + 1) = 0

Reorder the terms:
(5 + c)(c + 1) = 0

Reorder the terms:
(5 + c)(1 + c) = 0

Multiply (5 + c) * (1 + c)
(5(1 + c) + c(1 + c)) = 0
((1 * 5 + c * 5) + c(1 + c)) = 0
((5 + 5c) + c(1 + c)) = 0
(5 + 5c + (1 * c + c * c)) = 0
(5 + 5c + (1c + c2)) = 0

Combine like terms: 5c + 1c = 6c
(5 + 6c + c2) = 0

Solving
5 + 6c + c2 = 0

Solving for variable 'c'.

Factor a trinomial.
(5 + c)(1 + c) = 0

Subproblem 1

Set the factor '(5 + c)' equal to zero and attempt to solve: Simplifying 5 + c = 0 Solving 5 + c = 0 Move all terms containing c to the left, all other terms to the right. Add '-5' to each side of the equation. 5 + -5 + c = 0 + -5 Combine like terms: 5 + -5 = 0 0 + c = 0 + -5 c = 0 + -5 Combine like terms: 0 + -5 = -5 c = -5 Simplifying c = -5

Subproblem 2

Set the factor '(1 + c)' equal to zero and attempt to solve: Simplifying 1 + c = 0 Solving 1 + c = 0 Move all terms containing c to the left, all other terms to the right. Add '-1' to each side of the equation. 1 + -1 + c = 0 + -1 Combine like terms: 1 + -1 = 0 0 + c = 0 + -1 c = 0 + -1 Combine like terms: 0 + -1 = -1 c = -1 Simplifying c = -1

Solution

c = {-5, -1}

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