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Simplifying (c + 5)(c + -12) = 0 Reorder the terms: (5 + c)(c + -12) = 0 Reorder the terms: (5 + c)(-12 + c) = 0 Multiply (5 + c) * (-12 + c) (5(-12 + c) + c(-12 + c)) = 0 ((-12 * 5 + c * 5) + c(-12 + c)) = 0 ((-60 + 5c) + c(-12 + c)) = 0 (-60 + 5c + (-12 * c + c * c)) = 0 (-60 + 5c + (-12c + c2)) = 0 Combine like terms: 5c + -12c = -7c (-60 + -7c + c2) = 0 Solving -60 + -7c + c2 = 0 Solving for variable 'c'. Factor a trinomial. (-5 + -1c)(12 + -1c) = 0Subproblem 1
Set the factor '(-5 + -1c)' equal to zero and attempt to solve: Simplifying -5 + -1c = 0 Solving -5 + -1c = 0 Move all terms containing c to the left, all other terms to the right. Add '5' to each side of the equation. -5 + 5 + -1c = 0 + 5 Combine like terms: -5 + 5 = 0 0 + -1c = 0 + 5 -1c = 0 + 5 Combine like terms: 0 + 5 = 5 -1c = 5 Divide each side by '-1'. c = -5 Simplifying c = -5Subproblem 2
Set the factor '(12 + -1c)' equal to zero and attempt to solve: Simplifying 12 + -1c = 0 Solving 12 + -1c = 0 Move all terms containing c to the left, all other terms to the right. Add '-12' to each side of the equation. 12 + -12 + -1c = 0 + -12 Combine like terms: 12 + -12 = 0 0 + -1c = 0 + -12 -1c = 0 + -12 Combine like terms: 0 + -12 = -12 -1c = -12 Divide each side by '-1'. c = 12 Simplifying c = 12Solution
c = {-5, 12}
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