(c+5)(c-3)=

Solution for (c+5)(c-3)= equation:

Simplifying
(c + 5)(c + -3) = 0

Reorder the terms:
(5 + c)(c + -3) = 0

Reorder the terms:
(5 + c)(-3 + c) = 0

Multiply (5 + c) * (-3 + c)
(5(-3 + c) + c(-3 + c)) = 0
((-3 * 5 + c * 5) + c(-3 + c)) = 0
((-15 + 5c) + c(-3 + c)) = 0
(-15 + 5c + (-3 * c + c * c)) = 0
(-15 + 5c + (-3c + c2)) = 0

Combine like terms: 5c + -3c = 2c
(-15 + 2c + c2) = 0

Solving
-15 + 2c + c2 = 0

Solving for variable 'c'.

Factor a trinomial.
(-5 + -1c)(3 + -1c) = 0

Subproblem 1
Set the factor '(-5 + -1c)' equal to zero and attempt to solve:

Simplifying
-5 + -1c = 0

Solving
-5 + -1c = 0

Move all terms containing c to the left, all other terms to the right.

Add '5' to each side of the equation.
-5 + 5 + -1c = 0 + 5

Combine like terms: -5 + 5 = 0
0 + -1c = 0 + 5
-1c = 0 + 5

Combine like terms: 0 + 5 = 5
-1c = 5

Divide each side by '-1'.
c = -5

Simplifying
c = -5
Subproblem 2
Set the factor '(3 + -1c)' equal to zero and attempt to solve:

Simplifying
3 + -1c = 0

Solving
3 + -1c = 0

Move all terms containing c to the left, all other terms to the right.

Add '-3' to each side of the equation.
3 + -3 + -1c = 0 + -3

Combine like terms: 3 + -3 = 0
0 + -1c = 0 + -3
-1c = 0 + -3

Combine like terms: 0 + -3 = -3
-1c = -3

Divide each side by '-1'.
c = 3

Simplifying
c = 3
Solution
c = {-5, 3}