(c-1)(c-1)=0

Solution for (c-1)(c-1)=0 equation:

Simplifying
(c + -1)(c + -1) = 0

Reorder the terms:
(-1 + c)(c + -1) = 0

Reorder the terms:
(-1 + c)(-1 + c) = 0

Multiply (-1 + c) * (-1 + c)
(-1(-1 + c) + c(-1 + c)) = 0
((-1 * -1 + c * -1) + c(-1 + c)) = 0
((1 + -1c) + c(-1 + c)) = 0
(1 + -1c + (-1 * c + c * c)) = 0
(1 + -1c + (-1c + c2)) = 0

Combine like terms: -1c + -1c = -2c
(1 + -2c + c2) = 0

Solving
1 + -2c + c2 = 0

Solving for variable 'c'.

Factor a trinomial.
(1 + -1c)(1 + -1c) = 0

Subproblem 1
Set the factor '(1 + -1c)' equal to zero and attempt to solve:

Simplifying
1 + -1c = 0

Solving
1 + -1c = 0

Move all terms containing c to the left, all other terms to the right.

Add '-1' to each side of the equation.
1 + -1 + -1c = 0 + -1

Combine like terms: 1 + -1 = 0
0 + -1c = 0 + -1
-1c = 0 + -1

Combine like terms: 0 + -1 = -1
-1c = -1

Divide each side by '-1'.
c = 1

Simplifying
c = 1
Subproblem 2
Set the factor '(1 + -1c)' equal to zero and attempt to solve:

Simplifying
1 + -1c = 0

Solving
1 + -1c = 0

Move all terms containing c to the left, all other terms to the right.

Add '-1' to each side of the equation.
1 + -1 + -1c = 0 + -1

Combine like terms: 1 + -1 = 0
0 + -1c = 0 + -1
-1c = 0 + -1

Combine like terms: 0 + -1 = -1
-1c = -1

Divide each side by '-1'.
c = 1

Simplifying
c = 1
Solution
c = {1, 1}