(c-1)/4+(2c+3)/6=c-1

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Solution for (c-1)/4+(2c+3)/6=c-1 equation: 



(c-1)/4+(2c+3)/6=c-1

We move all terms to the left:

(c-1)/4+(2c+3)/6-(c-1)=0

We get rid of parentheses

(c-1)/4+(2c+3)/6-c+1=0

We calculate fractions

There is no solution for this equation

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