(c-10)(c-20)=

Solution for (c-10)(c-20)= equation:

Simplifying
(c + -10)(c + -20) = 0

Reorder the terms:
(-10 + c)(c + -20) = 0

Reorder the terms:
(-10 + c)(-20 + c) = 0

Multiply (-10 + c) * (-20 + c)
(-10(-20 + c) + c(-20 + c)) = 0
((-20 * -10 + c * -10) + c(-20 + c)) = 0
((200 + -10c) + c(-20 + c)) = 0
(200 + -10c + (-20 * c + c * c)) = 0
(200 + -10c + (-20c + c2)) = 0

Combine like terms: -10c + -20c = -30c
(200 + -30c + c2) = 0

Solving
200 + -30c + c2 = 0

Solving for variable 'c'.

Factor a trinomial.
(10 + -1c)(20 + -1c) = 0

Subproblem 1
Set the factor '(10 + -1c)' equal to zero and attempt to solve:

Simplifying
10 + -1c = 0

Solving
10 + -1c = 0

Move all terms containing c to the left, all other terms to the right.

Add '-10' to each side of the equation.
10 + -10 + -1c = 0 + -10

Combine like terms: 10 + -10 = 0
0 + -1c = 0 + -10
-1c = 0 + -10

Combine like terms: 0 + -10 = -10
-1c = -10

Divide each side by '-1'.
c = 10

Simplifying
c = 10
Subproblem 2
Set the factor '(20 + -1c)' equal to zero and attempt to solve:

Simplifying
20 + -1c = 0

Solving
20 + -1c = 0

Move all terms containing c to the left, all other terms to the right.

Add '-20' to each side of the equation.
20 + -20 + -1c = 0 + -20

Combine like terms: 20 + -20 = 0
0 + -1c = 0 + -20
-1c = 0 + -20

Combine like terms: 0 + -20 = -20
-1c = -20

Divide each side by '-1'.
c = 20

Simplifying
c = 20
Solution
c = {10, 20}