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Simplifying (c + -2)(c + -2) = 0 Reorder the terms: (-2 + c)(c + -2) = 0 Reorder the terms: (-2 + c)(-2 + c) = 0 Multiply (-2 + c) * (-2 + c) (-2(-2 + c) + c(-2 + c)) = 0 ((-2 * -2 + c * -2) + c(-2 + c)) = 0 ((4 + -2c) + c(-2 + c)) = 0 (4 + -2c + (-2 * c + c * c)) = 0 (4 + -2c + (-2c + c2)) = 0 Combine like terms: -2c + -2c = -4c (4 + -4c + c2) = 0 Solving 4 + -4c + c2 = 0 Solving for variable 'c'. Factor a trinomial. (2 + -1c)(2 + -1c) = 0Subproblem 1
Set the factor '(2 + -1c)' equal to zero and attempt to solve: Simplifying 2 + -1c = 0 Solving 2 + -1c = 0 Move all terms containing c to the left, all other terms to the right. Add '-2' to each side of the equation. 2 + -2 + -1c = 0 + -2 Combine like terms: 2 + -2 = 0 0 + -1c = 0 + -2 -1c = 0 + -2 Combine like terms: 0 + -2 = -2 -1c = -2 Divide each side by '-1'. c = 2 Simplifying c = 2Subproblem 2
Set the factor '(2 + -1c)' equal to zero and attempt to solve: Simplifying 2 + -1c = 0 Solving 2 + -1c = 0 Move all terms containing c to the left, all other terms to the right. Add '-2' to each side of the equation. 2 + -2 + -1c = 0 + -2 Combine like terms: 2 + -2 = 0 0 + -1c = 0 + -2 -1c = 0 + -2 Combine like terms: 0 + -2 = -2 -1c = -2 Divide each side by '-1'. c = 2 Simplifying c = 2Solution
c = {2, 2}
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