(c-2)*(c+1)=0

Solution for (c-2)*(c+1)=0 equation:

Simplifying
(c + -2)(c + 1) = 0

Reorder the terms:
(-2 + c)(c + 1) = 0

Reorder the terms:
(-2 + c)(1 + c) = 0

Multiply (-2 + c) * (1 + c)
(-2(1 + c) + c(1 + c)) = 0
((1 * -2 + c * -2) + c(1 + c)) = 0
((-2 + -2c) + c(1 + c)) = 0
(-2 + -2c + (1 * c + c * c)) = 0
(-2 + -2c + (1c + c2)) = 0

Combine like terms: -2c + 1c = -1c
(-2 + -1c + c2) = 0

Solving
-2 + -1c + c2 = 0

Solving for variable 'c'.

Factor a trinomial.
(-1 + -1c)(2 + -1c) = 0

Subproblem 1
Set the factor '(-1 + -1c)' equal to zero and attempt to solve:

Simplifying
-1 + -1c = 0

Solving
-1 + -1c = 0

Move all terms containing c to the left, all other terms to the right.

Add '1' to each side of the equation.
-1 + 1 + -1c = 0 + 1

Combine like terms: -1 + 1 = 0
0 + -1c = 0 + 1
-1c = 0 + 1

Combine like terms: 0 + 1 = 1
-1c = 1

Divide each side by '-1'.
c = -1

Simplifying
c = -1
Subproblem 2
Set the factor '(2 + -1c)' equal to zero and attempt to solve:

Simplifying
2 + -1c = 0

Solving
2 + -1c = 0

Move all terms containing c to the left, all other terms to the right.

Add '-2' to each side of the equation.
2 + -2 + -1c = 0 + -2

Combine like terms: 2 + -2 = 0
0 + -1c = 0 + -2
-1c = 0 + -2

Combine like terms: 0 + -2 = -2
-1c = -2

Divide each side by '-1'.
c = 2

Simplifying
c = 2
Solution
c = {-1, 2}