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Simplifying (c + -21)(c + 12) = 0 Reorder the terms: (-21 + c)(c + 12) = 0 Reorder the terms: (-21 + c)(12 + c) = 0 Multiply (-21 + c) * (12 + c) (-21(12 + c) + c(12 + c)) = 0 ((12 * -21 + c * -21) + c(12 + c)) = 0 ((-252 + -21c) + c(12 + c)) = 0 (-252 + -21c + (12 * c + c * c)) = 0 (-252 + -21c + (12c + c2)) = 0 Combine like terms: -21c + 12c = -9c (-252 + -9c + c2) = 0 Solving -252 + -9c + c2 = 0 Solving for variable 'c'. Factor a trinomial. (-12 + -1c)(21 + -1c) = 0Subproblem 1
Set the factor '(-12 + -1c)' equal to zero and attempt to solve: Simplifying -12 + -1c = 0 Solving -12 + -1c = 0 Move all terms containing c to the left, all other terms to the right. Add '12' to each side of the equation. -12 + 12 + -1c = 0 + 12 Combine like terms: -12 + 12 = 0 0 + -1c = 0 + 12 -1c = 0 + 12 Combine like terms: 0 + 12 = 12 -1c = 12 Divide each side by '-1'. c = -12 Simplifying c = -12Subproblem 2
Set the factor '(21 + -1c)' equal to zero and attempt to solve: Simplifying 21 + -1c = 0 Solving 21 + -1c = 0 Move all terms containing c to the left, all other terms to the right. Add '-21' to each side of the equation. 21 + -21 + -1c = 0 + -21 Combine like terms: 21 + -21 = 0 0 + -1c = 0 + -21 -1c = 0 + -21 Combine like terms: 0 + -21 = -21 -1c = -21 Divide each side by '-1'. c = 21 Simplifying c = 21Solution
c = {-12, 21}
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