(c-25)(c+5)=0

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Solution for (c-25)(c+5)=0 equation:


Simplifying
(c + -25)(c + 5) = 0

Reorder the terms:
(-25 + c)(c + 5) = 0

Reorder the terms:
(-25 + c)(5 + c) = 0

Multiply (-25 + c) * (5 + c)
(-25(5 + c) + c(5 + c)) = 0
((5 * -25 + c * -25) + c(5 + c)) = 0
((-125 + -25c) + c(5 + c)) = 0
(-125 + -25c + (5 * c + c * c)) = 0
(-125 + -25c + (5c + c2)) = 0

Combine like terms: -25c + 5c = -20c
(-125 + -20c + c2) = 0

Solving
-125 + -20c + c2 = 0

Solving for variable 'c'.

Factor a trinomial.
(-5 + -1c)(25 + -1c) = 0

Subproblem 1

Set the factor '(-5 + -1c)' equal to zero and attempt to solve: Simplifying -5 + -1c = 0 Solving -5 + -1c = 0 Move all terms containing c to the left, all other terms to the right. Add '5' to each side of the equation. -5 + 5 + -1c = 0 + 5 Combine like terms: -5 + 5 = 0 0 + -1c = 0 + 5 -1c = 0 + 5 Combine like terms: 0 + 5 = 5 -1c = 5 Divide each side by '-1'. c = -5 Simplifying c = -5

Subproblem 2

Set the factor '(25 + -1c)' equal to zero and attempt to solve: Simplifying 25 + -1c = 0 Solving 25 + -1c = 0 Move all terms containing c to the left, all other terms to the right. Add '-25' to each side of the equation. 25 + -25 + -1c = 0 + -25 Combine like terms: 25 + -25 = 0 0 + -1c = 0 + -25 -1c = 0 + -25 Combine like terms: 0 + -25 = -25 -1c = -25 Divide each side by '-1'. c = 25 Simplifying c = 25

Solution

c = {-5, 25}

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