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Simplifying (c + -25)(c + 50) = 0 Reorder the terms: (-25 + c)(c + 50) = 0 Reorder the terms: (-25 + c)(50 + c) = 0 Multiply (-25 + c) * (50 + c) (-25(50 + c) + c(50 + c)) = 0 ((50 * -25 + c * -25) + c(50 + c)) = 0 ((-1250 + -25c) + c(50 + c)) = 0 (-1250 + -25c + (50 * c + c * c)) = 0 (-1250 + -25c + (50c + c2)) = 0 Combine like terms: -25c + 50c = 25c (-1250 + 25c + c2) = 0 Solving -1250 + 25c + c2 = 0 Solving for variable 'c'. Factor a trinomial. (-50 + -1c)(25 + -1c) = 0Subproblem 1
Set the factor '(-50 + -1c)' equal to zero and attempt to solve: Simplifying -50 + -1c = 0 Solving -50 + -1c = 0 Move all terms containing c to the left, all other terms to the right. Add '50' to each side of the equation. -50 + 50 + -1c = 0 + 50 Combine like terms: -50 + 50 = 0 0 + -1c = 0 + 50 -1c = 0 + 50 Combine like terms: 0 + 50 = 50 -1c = 50 Divide each side by '-1'. c = -50 Simplifying c = -50Subproblem 2
Set the factor '(25 + -1c)' equal to zero and attempt to solve: Simplifying 25 + -1c = 0 Solving 25 + -1c = 0 Move all terms containing c to the left, all other terms to the right. Add '-25' to each side of the equation. 25 + -25 + -1c = 0 + -25 Combine like terms: 25 + -25 = 0 0 + -1c = 0 + -25 -1c = 0 + -25 Combine like terms: 0 + -25 = -25 -1c = -25 Divide each side by '-1'. c = 25 Simplifying c = 25Solution
c = {-50, 25}
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