(c-5)/4c=3/2

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Solution for (c-5)/4c=3/2 equation: 



(c-5)/4c=3/2

We move all terms to the left:

(c-5)/4c-(3/2)=0



Domain of the equation: 4c!=0

c!=0/4

c!=0

c∈R



We add all the numbers together, and all the variables

(c-5)/4c-(+3/2)=0

We get rid of parentheses

(c-5)/4c-3/2=0

We calculate fractions


(2c-10)/8c+(-12c)/8c=0

We multiply all the terms by the denominator


(2c-10)+(-12c)=0

We get rid of parentheses

2c-12c-10=0

We add all the numbers together, and all the variables

-10c-10=0

We move all terms containing c to the left, all other terms to the right

-10c=10

c=10/-10

c=-1

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