(c/5)-(2/c)=(7c+6)/35

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Solution for (c/5)-(2/c)=(7c+6)/35 equation: 


D( c )

c = 0

c = 0

c = 0

c in (-oo:0) U (0:+oo)

c/5-(2/c) = (7*c+6)/35 // - (7*c+6)/35

c/5-((7*c+6)/35)-(2/c) = 0

c/5-((7*c+6)/35)-2*c^-1 = 0

(-1*(7*c+6))/35+c/5-2/c = 0

(-1*5*c*(7*c+6))/(5*35*c)+(35*c^2)/(5*35*c)+(-2*5*35)/(5*35*c) = 0

35*c^2-1*5*c*(7*c+6)-2*5*35 = 0

-30*c-350 = 0

(-30*c-350)/(5*35*c) = 0

(-30*c-350)/(5*35*c) = 0 // * 5*35*c

-30*c-350 = 0

-30*c-350 = 0 // + 350

-30*c = 350 // : -30

c = 350/(-30)

c = -35/3

c = -35/3

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