(d+2)(d+2)-d(d+3)=37

Solution for (d+2)(d+2)-d(d+3)=37 equation:

Simplifying
(d + 2)(d + 2) + -1d(d + 3) = 37

Reorder the terms:
(2 + d)(d + 2) + -1d(d + 3) = 37

Reorder the terms:
(2 + d)(2 + d) + -1d(d + 3) = 37

Multiply (2 + d) * (2 + d)
(2(2 + d) + d(2 + d)) + -1d(d + 3) = 37
((2 * 2 + d * 2) + d(2 + d)) + -1d(d + 3) = 37
((4 + 2d) + d(2 + d)) + -1d(d + 3) = 37
(4 + 2d + (2 * d + d * d)) + -1d(d + 3) = 37
(4 + 2d + (2d + d2)) + -1d(d + 3) = 37

Combine like terms: 2d + 2d = 4d
(4 + 4d + d2) + -1d(d + 3) = 37

Reorder the terms:
4 + 4d + d2 + -1d(3 + d) = 37
4 + 4d + d2 + (3 * -1d + d * -1d) = 37
4 + 4d + d2 + (-3d + -1d2) = 37

Reorder the terms:
4 + 4d + -3d + d2 + -1d2 = 37

Combine like terms: 4d + -3d = 1d
4 + 1d + d2 + -1d2 = 37

Combine like terms: d2 + -1d2 = 0
4 + 1d + 0 = 37
4 + 1d = 37

Solving
4 + 1d = 37

Solving for variable 'd'.

Move all terms containing d to the left, all other terms to the right.

Add '-4' to each side of the equation.
4 + -4 + 1d = 37 + -4

Combine like terms: 4 + -4 = 0
0 + 1d = 37 + -4
1d = 37 + -4

Combine like terms: 37 + -4 = 33
1d = 33

Divide each side by '1'.
d = 33

Simplifying
d = 33