(d+2)(d+5)=0

Solution for (d+2)(d+5)=0 equation:

Simplifying
(d + 2)(d + 5) = 0

Reorder the terms:
(2 + d)(d + 5) = 0

Reorder the terms:
(2 + d)(5 + d) = 0

Multiply (2 + d) * (5 + d)
(2(5 + d) + d(5 + d)) = 0
((5 * 2 + d * 2) + d(5 + d)) = 0
((10 + 2d) + d(5 + d)) = 0
(10 + 2d + (5 * d + d * d)) = 0
(10 + 2d + (5d + d2)) = 0

Combine like terms: 2d + 5d = 7d
(10 + 7d + d2) = 0

Solving
10 + 7d + d2 = 0

Solving for variable 'd'.

Factor a trinomial.
(5 + d)(2 + d) = 0

Subproblem 1
Set the factor '(5 + d)' equal to zero and attempt to solve:

Simplifying
5 + d = 0

Solving
5 + d = 0

Move all terms containing d to the left, all other terms to the right.

Add '-5' to each side of the equation.
5 + -5 + d = 0 + -5

Combine like terms: 5 + -5 = 0
0 + d = 0 + -5
d = 0 + -5

Combine like terms: 0 + -5 = -5
d = -5

Simplifying
d = -5
Subproblem 2
Set the factor '(2 + d)' equal to zero and attempt to solve:

Simplifying
2 + d = 0

Solving
2 + d = 0

Move all terms containing d to the left, all other terms to the right.

Add '-2' to each side of the equation.
2 + -2 + d = 0 + -2

Combine like terms: 2 + -2 = 0
0 + d = 0 + -2
d = 0 + -2

Combine like terms: 0 + -2 = -2
d = -2

Simplifying
d = -2
Solution
d = {-5, -2}