(d+2)+(3d+4)-10=16

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Solution for (d+2)+(3d+4)-10=16 equation:


Simplifying
(d + 2) + (3d + 4) + -10 = 16

Reorder the terms:
(2 + d) + (3d + 4) + -10 = 16

Remove parenthesis around (2 + d)
2 + d + (3d + 4) + -10 = 16

Reorder the terms:
2 + d + (4 + 3d) + -10 = 16

Remove parenthesis around (4 + 3d)
2 + d + 4 + 3d + -10 = 16

Reorder the terms:
2 + 4 + -10 + d + 3d = 16

Combine like terms: 2 + 4 = 6
6 + -10 + d + 3d = 16

Combine like terms: 6 + -10 = -4
-4 + d + 3d = 16

Combine like terms: d + 3d = 4d
-4 + 4d = 16

Solving
-4 + 4d = 16

Solving for variable 'd'.

Move all terms containing d to the left, all other terms to the right.

Add '4' to each side of the equation.
-4 + 4 + 4d = 16 + 4

Combine like terms: -4 + 4 = 0
0 + 4d = 16 + 4
4d = 16 + 4

Combine like terms: 16 + 4 = 20
4d = 20

Divide each side by '4'.
d = 5

Simplifying
d = 5

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