(d+2)+(4d+3)-10=15

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Solution for (d+2)+(4d+3)-10=15 equation:


Simplifying
(d + 2) + (4d + 3) + -10 = 15

Reorder the terms:
(2 + d) + (4d + 3) + -10 = 15

Remove parenthesis around (2 + d)
2 + d + (4d + 3) + -10 = 15

Reorder the terms:
2 + d + (3 + 4d) + -10 = 15

Remove parenthesis around (3 + 4d)
2 + d + 3 + 4d + -10 = 15

Reorder the terms:
2 + 3 + -10 + d + 4d = 15

Combine like terms: 2 + 3 = 5
5 + -10 + d + 4d = 15

Combine like terms: 5 + -10 = -5
-5 + d + 4d = 15

Combine like terms: d + 4d = 5d
-5 + 5d = 15

Solving
-5 + 5d = 15

Solving for variable 'd'.

Move all terms containing d to the left, all other terms to the right.

Add '5' to each side of the equation.
-5 + 5 + 5d = 15 + 5

Combine like terms: -5 + 5 = 0
0 + 5d = 15 + 5
5d = 15 + 5

Combine like terms: 15 + 5 = 20
5d = 20

Divide each side by '5'.
d = 4

Simplifying
d = 4

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